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in Sets, Relations and Functions by (46.3k points)
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Given ξ = { x : x is a natural number} 

A = { x : x is an even number, x ∈ N} 

B = { x : x is an odd number, x ∈ N} 

Then (B ∩ A) – ( x – A} = .....

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A = { 2, 4, 6, 8, ..... } 

B = { 1, 3, 5, 7, .... } 

B ∩ A = { 2, 4, 6, 8 , .....} ∩ { 1, 3, 5, 7, .....} = ϕ 

ξ – A = {1, 2, 3, 4, 5, 6, .....} – { 2, 4, 6, 8, .....} 

= { 1, 3, 5, 7, ....} 

∴ B ∩ A – ( ξ –A) = ϕ – {1, 3, 5, 7, .....} = ϕ

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