(b) 2 only
1. A – ( B – C) = A – (B ∩ C′)
= A ∩ (B ∩ C′)′
= A ∩ (B′ ∪ (C′)′)
= A ∩ (B′ ∪ C)
(Α – Β) ∪ C = (A ∩ B′) ∪ C
Thus, A – ( B – C) ≠ (A – B) ∪ C
2. A – ( B ∪ C) = A ∩ (B ∩ C)′
= A ∩ (B′ ∩ C′)
(A – B) – C = (A ∩ B′) – C
= A ∩ B′ ∩ C′
⇒ A – (B ∪ C) = (A – B) – C
Associative property.