Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
612 views
in Sets, Relations and Functions by (46.3k points)
closed by

If n (A) = 65, n (B) = 32 and n (A ∩ B) = 14, then n (A Δ B) equals

(a) 65 

(b) 47 

(c) 97 

(d) 69

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

(d) 69

n (A Δ B) = n (A – B) + n (B – A) 

∴ A Δ B = (A – B) ∪ ( B – A) 

= n (A) – n (A ∩ B) + n (B) – n (A ∩ B) 

= n (A) + n (B) – 2n (A ∩ B) 

= 65 + 32 – 2 × 14 = 69.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...