(i) Let A be the event of drawing a red from urn 1,
P(A) = \(\frac{6}{25}\)
Let B be the event of selecting a red ball in urn 2.
P(B) = \(\frac{7}{25}\)
∴ P(both balls are red) = P(A).P(B) [∵ the events are independent]
= \(\frac{6}{25}\) x \(\frac{7}{25}\)
= \(\frac{42}{625}\)
Let W1, R1, B1 represents white, red, and black balls drawn from urn 1 and W2, R2, B2 represents white, red, and black balls from urn 2.
(ii) P(both balls are of the same colour) = P(W1W2) + P(R1R2) + P(B1B2) [∵ Events are mutually exclusive]
= P(W1) P(W2) + P(R1) P(R2) + P(B1) P(B2) [∵ Events are independent]