(c) trapezium
Let the angles of the quadrilateral be 3\(x\), 7\(x\), 6\(x\) and 4\(x\).
Then, 3\(x\) + 7\(x\) + 6\(x\) + 4\(x\) = 360°
⇒ 20\(x\) = 360° ⇒ \(x\) = 18°
∴ The angles A, B, C and D are respectively 3 x 18°, 7 x 18°, 6 x 18° and 4 x 18°, i.e.,54°, 126°, 108° and 72°.
which shows that ∠A + ∠B = 180° and ∠C + ∠D = 180° ⇒ AD||BC.
Hence ABCD is a trapezium.