(d) 109°
In a kite, the two pairs of adjacent sides are equal, i.e., PS = PQ and SR = RQ
In ΔPSQ,
∠PSQ =∠PQS = \(\frac{180°-70°}{2}=\frac{110°}{2}\) = 55°
∴ ∠QSR = 90.5° – 55° = 35.5°
⇒ ∠RQS = ∠QSR = 35.5° (∵RQ = RS)
In ΔSRQ,
∠R +∠RQS +∠QSR = 180°
⇒ ∠R + 35.5° + 35.5° = 180°
⇒ ∠R = 180° – 71° = 109°.