(c) 41°
ΔAQD is an equilateral Δ
⇒ ∠QAD = ∠QDA = ∠AQD = 60°
∠BAD = 360° – (135° + 90° + 60°)
= 360° – 285° = 75° (Angles round a pt.)
Also, in quad. ABCD,
∠CDA = 360°– (100° + 106° + 75°)
= 360° – 281° = 79°.
∴ ∠PDQ =180° – (∠CDA+ ∠QDA) (CDP is a st. line)
= 180° – (79° + 60°) = 180° – 139° = 41°.