The probability of the product produced by machine A is P(A) = \(\frac{20}{100}\)
The probability of the product produced by machine B is P(B) = \(\frac{30}{100}\)
The probability of the product produced by the machine C is P(C) = \(\frac{50}{100}\)
Let D be the event of selecting a defective product.
Then P(\(\frac{D}{A}\)) = The probability of selecting a defective product produced by the machine A = \(\frac{7}{100}\)
P(\(\frac{D}{B}\)) = The probability of selecting a defective product produced by the machine B = \(\frac{3}{100}\)
And P(D/C) = The probability of selecting a detective product produced by the machine C = \(\frac{5}{100}\)