Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.5k views
in Polygons by (46.2k points)
closed by

Polygon A is a regular pentagon and polygon B is a regular hexagon. Find ∠\(x\).

(a) 108° 

(b) 132° 

(c) 124° 

(d) 96°

1 Answer

+1 vote
by (49.2k points)
selected by
 
Best answer

(b) 132°

∠a = \(\frac{(5-2)\times180°}{5}=108°\)   (Int. ∠ of a pentagon)

∠b = \(\frac{180°-180°}{2}=36°\)      (∵ ΔABC is isos.)

∠c = \(\frac{(6-2)\times180°}{6}=120°\)  (Int. ∠ of a hexagon)

∠e = 180° – 120° = 60°          ( ∵SR || QC, co-int. ∠s) 

∴ ∠x = ∠y – ∠b –∠e 

= ∠BCD + ∠DCS – ∠b – ∠e 

= 108° + 120° – 36° – 60° 

= 132°

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...