Given exp = \(\frac43\times\bigg(\frac{1}{\sqrt3}\bigg)^2+\bigg(\frac{\sqrt3}{2}\bigg)^2-3\times\big(\frac12\big)^2+\frac34\times(\sqrt3)^2-2\times(1)^2\)
= \(\frac43\times\frac13+\frac34-\frac34+\frac94-2\)
= \(\frac49+\frac94-2=\frac{16+81-72}{36}= \frac{25}{36}.\)