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Prove that : \(\frac43\) tan2 30° + sin2 60° – 3 cos2 60° + \(\frac34\) tan2 60° – 2 tan2 45° = \(\frac{25}{36}\)

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Given exp = \(\frac43\times\bigg(\frac{1}{\sqrt3}\bigg)^2+\bigg(\frac{\sqrt3}{2}\bigg)^2-3\times\big(\frac12\big)^2+\frac34\times(\sqrt3)^2-2\times(1)^2\)

\(\frac43\times\frac13+\frac34-\frac34+\frac94-2\)

\(\frac49+\frac94-2=\frac{16+81-72}{36}= \frac{25}{36}.\)

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