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Let a sample space of an experiment be S = {E1, E2, … , En} then \(\sum_{i=1}^{n} P(E_i)\) is equal to:

(a) 0 

(b) 1 

(c) \(\frac{1}{2}\)

(d) \(\frac{1}{3}\)

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(b) 1

Sum of probabilities is 1

i.e., \(\sum_{i=1}^{n} P(E_i)\) =  1

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