Question

The value of sin 0° + cos 30° – tan 45° + cosec 60° + cot 90° is equal to

(a) \(\frac{5\sqrt3-6}{6}\)

(b) \(\frac{-6+7\sqrt3}{6}\)

(c) 0 

(d) 2

Answer 1

(b) \(\frac{7\sqrt3-6}{6}.\)

Given exp. = \(0+\frac{\sqrt3}{2}-1+\frac{2}{\sqrt3}+0\)

= \(\frac{\sqrt3}{2}-1+\frac2{\sqrt3}=\frac{2\sqrt3+4}{2\sqrt3}=\frac{7-2\sqrt3}{2\sqrt3}\times\frac{\sqrt3}{\sqrt3}\)

= \(\frac{7\sqrt3-6}{6}.\)