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in Polynomials by (49.3k points)
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\(\sqrt{\frac{(x^2+3x+2)(x^2+5x+6)}{x^2(x^2+4x+3)}}\) is equal to :

(a) x (x +1) 

(b) \(\frac{x+2}{x}\)

(c) \(\frac{x}{x+2}\)

(d) x( x + 2)

1 Answer

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Best answer

(b) \(\frac{x+2}{x}\)

\(\sqrt{\frac{(x^2+3x+2)(x^2+5x+6)}{x^2(x^2+4x+3)}}\)

\(\sqrt\frac{(x+1)(x+2)(x+2)(x+3)}{x^2(x+1)(x+3)}\)

\(\sqrt{\frac{(x+2)^2}{x^2}}\) = \(\frac{x+2}{x}\)

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