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Simplify \(\bigg[\frac{1}{1+a} + \frac{2a}{1-a^2}\bigg]\times\frac{(a^2+4a-5)}{(a^2+10a+25)}\)

(a) \(\frac{-1}{a+1}\)

(b) \(\frac{1}{1-a}\)

(c) \(\frac{1}{a+5}\)

(d) \(\frac{-1}{a+5}\)

1 Answer

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Best answer

(d) \(\frac{-1}{a+5}\)

\(\bigg[\frac{1}{1+a} + \frac{2a}{1-a^2}\bigg]\times\frac{(a^2+4a-5)}{(a^2+10a+25)}\)

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