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in Algebraic Expressions by (49.3k points)
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The factors of 625a12 – 81b12 are :

(a) (25a6 + 9b6)(5a3 - 3b3)(5a3 + 3b3)

(b) (5a3 + 3b3)(5a3 - 3b3)2

(c) (5a3 - 3b3)4

(d) (25a6 - 9b6)2

1 Answer

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Best answer

(a) (5a3 - 3b3)(5a3 + 3b3)(25a6 + 9b6)

625a12 - 81b12

= (25a6)2 + (9b6)2

= (25a6 - 9b6) (25a6 + 9b6)

= [(5a3)2 - (3b3)2] (25a6 + 9b6)

= (5a3 - 3b3)(5a3 + 3b3)(25a6 + 9b6)

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