Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Algebraic Expressions by (49.3k points)
closed by

Factorise : a6  – 26a3  – 27

(a) (a - 3)(a + 1)(a2 + a + 1)(a2 + 3a + 9)

(b) (a - 3)(a - 1)(a2 + a + 1)(a2 + 3a + 9)

(c) (a - 3)(a + 1)(a2 + 3a + 9)(a2 - a + 1)

(d) (a + 3)(a 1 1)(a2 + 3a + 9)(a2 + a + 1)

1 Answer

+1 vote
by (46.3k points)
selected by
 
Best answer

(c) (a - 3)(a2 + 3a + 9)(a + 1)(a2 - a + 1)

a6 - 26a3 - 27

= a6 - 27 a3 + a3 - 27

 = a3 (a3 - 24) + 1(a3 - 27)

=(a3 - 27)(a3 + 1)

= (a - 3)(a2 + 3a + 9)(a + 1)(a2 - a + 1)

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...