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Find the square root of : 4a2 + 9b2 + c2 - 12ab + 6bc - 4ac

(a) (2a + 3b - c)

(b) (2a - 3b + c)

(c) (-2a + 3b + c)

(d) (-2a + 3b + c)

1 Answer

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Best answer

(c) (-2a + 3b + c)

4a2 + 9b2 + c2 - 12ab + 6bc - 4ac

= (-2a)2 + (3b)2 + c2 + 2 x (-2a) x 3b + 2 x 3b x c + 2 x (-2a) x c

= (-2a + 3b + c)2

∴ Reqd. sq. root = –2a + 3b + c

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