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A student uses a simple pendulum of exactly 1m length to determine g, the acceleration due to gravity.

Answer is 1, 3.
Please explain.

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Error in time period = least count/20 = 1/20 = 0.05 s

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It is given in the question that the least count of the stop watch is 1 second. Therefore the error in t (i.e. deltta t) should be 1 second.
Also we know that time period 't' means the total time taken for 1 ossilation. Here the time taken for 1 ossilation is 40/20=2 seconds. Therefore the time period should be 2 seconds and so the error % in g should be 100%. Could you please explain where am I wrong?

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