(i) Given length l = 12 m; Breadth b = 8 cm
∴ Area of rectangle = l x b sq. units = 12 x 8 m2
= 96 m2
Perimeter of the rectangle = 2 x (1 + b) units
= 2 x (12 + 8)m = 2 x 20 = 40m
(ii) Given Length l = 15 cm; Area of the rectangle = 90 sq. cm
l x b = 90; 15 x 6 = 90; b = \(\frac{90}{15}\) = 6 cm
Perimeter of the rectangle = 2 x (l + b) units = 2 x (15 + 6) cm = 2 x 21 cm
= 42 cm
(iii) Given Breadth of rectangle = 50 mm; Perimeter of the rectangle = 300 mm
2 x (l + b) = 300
2 x (l + 50) = 300
l + 50 = \(\frac{300}{2}\) = 150
l = 150 – 50
l = 100
Area = l x b sq. untis = 100 x 50 mm2 = 5000 mm2
(iv) Length of the rectangle = 12 cm; Perimeter = 44 cm
2(l + b) = 44
2(12 + b) = 44
12 + b = \(\frac{44}{2}\)
12 + b = 22; b = 22 – 12; b = 10 cm
Area = l x b sq. units
= 12 x 10 cm2 = 120 cm2
S. No. |
Length |
Breadth |
Area |
Perimeter |
(i) |
12 m |
8 m |
96 m2 |
40 m |
(ii) |
15 cm |
6 cm |
90 sq.cm |
42 cm |
(ii) |
100 mm |
50 mm |
5000 sq. m |
300 mm |
(iv) |
12 cm |
10 cm |
120 cm2 |
44 cm |