Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Measurements by (26.1k points)
closed by

Find the missing values for the following:

S. No. Length Breadth Area Perimeter
(i) 12 m 8 m
(ii) 15 cm 90 sq.cm
(ii) 50 mm 300 mm
(iv) 12 cm 44 cm

1 Answer

+1 vote
by (26.4k points)
selected by
 
Best answer

(i) Given length l = 12 m; Breadth b = 8 cm 

∴ Area of rectangle = l x b sq. units = 12 x 8 m2 

= 96 m2

Perimeter of the rectangle = 2 x (1 + b) units 

= 2 x (12 + 8)m = 2 x 20 = 40m

(ii) Given Length l = 15 cm; Area of the rectangle = 90 sq. cm 

l x b = 90; 15 x 6 = 90; b = \(\frac{90}{15}\) = 6 cm 

Perimeter of the rectangle = 2 x (l + b) units = 2 x (15 + 6) cm = 2 x 21 cm 

= 42 cm

(iii) Given Breadth of rectangle = 50 mm; Perimeter of the rectangle = 300 mm

2 x (l + b) = 300

2 x (l + 50) = 300

l + 50 = \(\frac{300}{2}\) = 150

l = 150 – 50

l = 100

Area = l x b sq. untis = 100 x 50 mm2 = 5000 mm2

(iv) Length of the rectangle = 12 cm; Perimeter = 44 cm

2(l + b) = 44

2(12 + b) = 44

12 + b = \(\frac{44}{2}\)

12 + b = 22; b = 22 – 12; b = 10 cm

Area = l x b sq. units

= 12 x 10 cm2 = 120 cm2

S. No. Length Breadth Area Perimeter
(i) 12 m 8 m 96 m2 40 m
(ii) 15 cm 6 cm  90 sq.cm 42 cm
(ii) 100 mm 50 mm 5000 sq. m 300 mm
(iv) 12 cm 10 cm 120 cm2 44 cm

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...