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How many numbers greater than 5000 can be formed with the digits 3, 5, 7, 8, 9 no digit being repeated?

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Obviously with the given 5-digits, numbers greater than 5000 are either 4-digit numbers having 5 or 7 or 8 or 9 at the thousand’s place or 5-digit numbers.

Since the thousand’s place in the required 4-digit numbers cannot take 3 as a value, we have 4 options for thousand’s place, the remaining 4 out of 5 (1 earning the one used up at thousand’s place) for hundred’s place, 3 for tens’ place and 2 for one’s place.

(Note: Repetition of digits is not allowed)

Four-Digit Numbers

Thousands Place
5, 7, 8 or 9
Hundreds Place
Any of the 4 remaining digits
Tens Place
Any of the remaining 3 digits
Ones Place
Any of the remaining 2 digits
4 ways 4 ways 3 ways 2 ways

∴ Number of 4-digit numbers greater than 5000 

That can be formed with given digits = 4 × 4 × 3 × 2 = 96 

For the 5-digit numbers, the various places can be filled up as shown:

∴ Number of 5-digit numbers = 5 × 4 × 3 × 2 × 1 = 120. 

∴ Total required numbers = 96 + 120 = 216.

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