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in Permutations by (46.2k points)
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How many integers of four digits can be formed with the digits 0, 1, 3, 5, 6 (assuming no repetitions)? 

(a) 96 

(b) 120 

(c) 15 

(d) 625

1 Answer

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Best answer

(a) 96.

The thousands’ place cannot be occupied by 0, as the number will then become three digit, so there are 4 choices for thousands’ place. As repetition is not allowed, so leaving the digit occupying thousands’ place, there are again 4 choices for hundreds’ place (including 0) 

Similarly for Tens’ place there 3 choices, for units’ place 2 choices. 

∴ Total number of 4-digit numbers without repetition of digits = 4 × 4 × 3 × 2 = 96.

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