Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.8k views
in Permutations by (46.3k points)
closed by

How many three-digit odd numbers can be formed by using the digits 1, 2, 3, 4, 5, 6 if repetition of digits is not allowed?

(a) 72 

(b) 108 

(c) 40 

(d) 60

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

(d) 60

For a number to be odd, we should have 1 or 3 or 5 at the unit’s place. So there are 3 ways of filling the unit’s place. 

As repetition of digits is not allowed, the ten’s place can be filled in 5 ways with any of the remaining 5-digts and the hundred’s place can be filled in 4 ways by the remaining 4-digits. So, 

Required number of three-digit odd numbers = 3 × 5 × 4 = 60.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...