(c) 24
Numbers greater than 60000 will have either 6 or 8 in the TTh place and will consist of 5-digits.
If the digit 6 occupies the TTh place, the remaining 4 places can be occupied in \(\frac{4!}{2!}\) ways. (∵ There are two 2’s)
Number of numbers beginning with 6 = \(\frac{4!}{2!}\) = 12
Similarly, number of numbers beginning with 8 = \(\frac{4!}{2!}\) = 12
∴ Number of different numbers greater than 60000 formed with digits 0, 2, 2, 6, 8
= 12 + 12 = 24.
