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A committee of 11 members sit at a round table. In how many ways can they be seated if the “President” and the “Secretary” choose to sit together.

(a) \(\frac{10!}{2!}\) 

(b) \(\frac{9!}{2!}\)

(c) 9 ! × 2 ! 

(d) \(\frac{11!}{2!}\)

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(c) 9! x 2!

Considering the president and secretary as one member, we have now 10 members in all. These 10 members can be seated round the circular table in (10 – 1)! = 9! ways. Also the president and secretary can seat themselves in 2! ways PS or SP 

∴ Required number of ways of seating = 9! × 2!.

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