(b) 132
As each team of 11 players has one goalkeeper and 10 team members, and out of 14 players there are 2 goalkeepers and 12 team members.
So the number of ways in which a team of 11 can be selected
= 12C10 x 2C1 \(\frac{12!}{10!\times2!}\times2\)
= \(\frac{12\times11}{2}\times2\) = 132.