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A man has 6 friends. Number of different ways, he can invite 2 or more for dinner is

(a) 28 

(b) 57 

(c) 71 

(d) 96

1 Answer

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Best answer

(b) 57

He can write 2 or more friends out of 6 friends in the given number of ways: 

Invite (i) 2 friends out of 6 friends or 

(ii) 3 friends out of 6 friends or 

(iii) 4 friends out of 6 friends or 

(iv) 5 friends out of 6 friends or 

(v) 6 friends out of 6 friends. 

∴ Total number of ways of inviting 2 or more friends 

= 6C2 + 6C3 + 6C4 + 6C5 + 6C6 

= \(\frac{6!}{4!2!}\) + \(\frac{6!}{3!3!}\) + \(\frac{6!}{4!2!}\) + \(\frac{6!}{5!1!}\) + \(\frac{6!}{6!}\) 

= \(\frac{6\times5}{2}\) + \(\frac{6\times5\times4}{2}\) + \(\frac{6\times5}{2}\) + 6 + 1 

= 15 + 20 + 15 + 6 + 1 = 57.

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