(b) 11250 m3
If we take the vertical crossection of the face of the swimming pool, then it is a trapezium ABCD, with parallel sides AD and BC respectively of lengths 10 m and 20 m and distance between parallel sides as 50 m. The width of the swimming pool is 15 m.
∴ Volume of water in the swimming pool
= Area of vertical cross section (ABCD) × width of swimming pool
= \(\big[\frac12(10+20)\times50\big]\times15\) m3
= (15 x 50 x 15) m3 = 11250 m3.