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A solid right circular cylinder of radius 8 cm and height 2 cm is melted and cast into a right circular cone of height 3 times that of the cylinder. Find the curved surface of the cone ? 

(a) 54 π cm2 

(b) 80 π cm2

(c) 72 π cm2

(d) 77 π cm2

1 Answer

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Best answer

(b) 80π cm2

For cylinder, radius (r1) = 8 cm, height (h1) = 2 cm 

For cone, radius (r2) = ?, height (h2) = 6 cm 

Now, Volume of cone = Volume of cylinder

⇒ \(\frac13πr^2_2h_2= πr^2_1h_1\) ⇒ \(\frac13πr^2_2\times6 = ​​π\times8\times8\times2\)

⇒ \(r^2_2=\frac{π\times8\times8\times2\times3}{π\times6}=64\) ⇒ r2 = 8 cm

Curved surface of cone = πr2l = \(πr_2\sqrt{h^2_2+r^2_2}\)

= π x 8 x \(\sqrt{36\times64}=(π\times8\times10)\)cm= 80π cm2.

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