(b) 80π cm2
For cylinder, radius (r1) = 8 cm, height (h1) = 2 cm
For cone, radius (r2) = ?, height (h2) = 6 cm
Now, Volume of cone = Volume of cylinder
⇒ \(\frac13πr^2_2h_2= πr^2_1h_1\) ⇒ \(\frac13πr^2_2\times6 = π\times8\times8\times2\)
⇒ \(r^2_2=\frac{π\times8\times8\times2\times3}{π\times6}=64\) ⇒ r2 = 8 cm
Curved surface of cone = πr2l = \(πr_2\sqrt{h^2_2+r^2_2}\)
= π x 8 x \(\sqrt{36\times64}=(π\times8\times10)\)cm2 = 80π cm2.