(d) None of these
Volume of bigger sphere = \(\frac43\) x π x (10)3 cm3 = \(\frac{4000}{3}\)π cm3
Volume of each smaller sphere = \(\frac{\frac{4000}{3}}{1000}\) cm3 = \(\frac43\)π cm3
∴ If r is the radius of each smaller sphere, then
\(\frac43πr^3= \frac43π\) ⇒ r = 1 cm.
Surface area of bigger sphere = 4 x π x (10)2 cm2 = 400 π cm2
Surface area of 1000 smaller spheres = 1000 × (4 x π x 1)cm2 = 4000 π cm2
So, the total surface area increases by \(\frac{4000π -400π}{400π}\) times
= 9 times.