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(i) An element X-belongs to the second period of p-block. It has 6 electrons in the outermost shell. Name the element. 

(ii) How do the electronic configuration of the elements with Z = 107 to 109 differ from one another? 

(iii) Rn (Z = 86) is the last noble gas discovered. Predict what will be the atomic number of the next noble gas to be discovered. Write its symbol.

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(i) The outermost configuration of the element

= 2s2 2p4 (as it has 6 electrons in the outermost shell)

\(\therefore\) Electronic configuration of the element = 1s2 , 2s2 2p4

\(\therefore\) Atomic number = 2+ 2 + 4 = 8

Hence, the element is oxygen.

(ii) Element with Z = 107 has five, Z = 108 has six electrons while Z = 109 has seven 6d-eletrons. Hence, these elements differ in the number of electrons in the 6dsubshell.

(iii) Z = 86 Atomic number of next noble gas = 86 + 32 = 118 Its symbol is Uuo.

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