Question

Write the correctly balanced net ionic equation for the reaction whose equilibrium constant at 298 K is:

(i) k_a (C_aH₅COOH) = 6.3 x 10^-5

(ii) k_a (H₂C₂O₄) = 5.4 x 10^-2

(iii) k_a (HSO₃^-) = 2.8 x 10^-7

(iv) k_b (CC1^-) = 9.1 x 10^-7

(v) k_b (CH₃NH₂) = 4.2 x 10^-4

(vi) k_a (H₂S) = 1.0 x 10^-7

(vii) ka (HCN) = 4.0 x 10^-10

(viii) kb (NH₃) = 1.8 x 10^-5

(ix) ka (H₂S) = 1.0 x 10^-7

Answer 1

(i) C_aH₅COOH ⇌ C₆H₅COO⁻ + H⁺

(ii) H₂C₂O₄ ⇌ C₂O₄²⁻ + 2H⁺

(iii) HSO₃ ⇌ H⁺ + SO₃^2-

(iv) C1^-H₂O ⇌ OH^- + HC1

(v) CH₃NH₂ + H₂O ⇌ CH₃NH₃⁺ + OH^-

(vi) H₂S ⇌ H⁺ + HS^-

(vii) HCN ⇌ H⁺ + CN^-

(viii) NH₃ + H₂O ⇌ NH₄⁺ + OH^-

(ix) H₂S + 2H₂O ⇌ S₂^- + H₃O⁺