(d) (−∞ , -√2) ∪ ( √2, ∞)
Case I: When \(x\) + 2 > 0, then \(x\) > – 2
⇒ |\(x\) + 2| = \(x\) + 2
∴ x2 – |\(x\) + 2| + \(x\) > 0 = x2 – (\(x\) + 2) + \(x\) > 0
⇒ x2 – 2 > 0 ⇒ x2 > 2
⇒ \(x\) < -√2 or 2 \(x\) > √2
⇒ x∈ (– 2, − √2 ) ∪ ( 2 , ∞) [∵ \(x\) ≥ − 2] …(i)
Case II: When \(x\) + 2 < 0, then \(x\) < – 2
⇒ |\(x\) + 2| = – (\(x\) + 2)
∴ x2 – |\(x\) + 2| + \(x\) > 0 ⇒ x2 + (\(x\) + 2) + \(x\) > 0
⇒ x2 + 2x + 2 > 0 ⇒ (x2 + 2x + 1) + 1 > 0
⇒ (x + 1)2 + 1 > 0, which is true for all value of x.
∴ \(x\) < – 2 ⇒ \(x\)∈ (– ∞, – 2) …(ii)
From (i) and (ii)
\(x\)∈ (– 2, −√2) ∪ ( √2, ∞ ) ∪ (– ∞, – 2)
⇒ \(x\)∈ (−∞ , −√2) ∪ ( √2, ∞)