Given,
Equilibrium constant K = 2.0 x 1015
[Cu2+] = 1.8 x 10-2 mol L-1
[Ag+] = 3.0 x 10-9 mol L-1
For the reaction
Cu(S) + 2Ag+ (aq) ⇌ Cu2+ (aq) + 2Ag (s)
Equilibrium constant K = \(\frac{[Cu^{2+}]}{[Ag^+]^2}\)
2 x 105 = \(\frac{1.8\times10^{-2}}{(3.0\times10^{-9})^2}\)
= 2 x 1015
Hence, the reaction is at equilibrium.
(b) Law of Chemical Equilibrium: According to this law, "at a given temperature, the product of concentrations of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentrations of the reactants raised to their individual stoichiometric coefficients has a constant value.’’