# ​ Kc for the reaction SO2 + 1/2  O2 ⇌ SO3 at 600º C is 61.7. Calculate Kp. What is the unit of Kp for the above equilibrium? ​

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Kc for the reaction SO2 + $\frac{1}{2}$ O2 ⇌ SO3 at 600º C is 61.7. Calculate Kp. What is the unit of Kp for the above equilibrium? (R = 0.0821 L atm degree-1 mol-1 )

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For the reaction

SO2 + $\frac{1}{2}$ O2 ⇌ SO3

Given, Kc = 61.7

T = 600 + 273 = 873K

∆n = No. of moles of product - No. of moles of Reactants

= 1 − (1 + $\frac{1}{2}$ )

= −  $\frac{1}{2}$

∴ Kp = Kc (RT)

= 61.7(0.0821 × 873)$\frac{1}{2}$

= 7.29

Kp$\frac{(P_{SO_3})}{(P_{SO_2}).(P_{O_2})^{\frac{1}{2}}}$

$\frac{atm}{atm.(atm)^{\frac{1}{2}}}$

$atm^{-\frac{1}{2}}$

∴ The unit of Kp for the above equilibrium is $atm^{-\frac{1}{2}}$