Let the concentration of AgCl is x mol/L and concentration of CuCl is mol/L
Ksp of AgCl= [Ag+][Cl−]
= x (x + y) ...........(i)
Ksp of CuCl = [Cu+][Cl−]
= y ( x + y) .........(ii)
On solving equation (i) and (ii), we get
\(\frac{K_{sp}\,of\,AgCl}{K_{sp}\,of\,CuCl}\) = \(\frac{X}{y}\)
\(\frac{1.6\times10^{-10}}{1.0\times10^{-6}}\) = \(\frac{X}{0.1}\)
or x = \(\frac{1.6\times10^{-10}\times0.1}{1.0\times10^{-6}}\)
= 1.6 x 10-5 mol/L