Question

If p = -2, q = 1 and r = 3, find the value of 3p²q²r.

Answer 1

Given p = -2; 

q = 1; 

r = 3

∴ 3p²q²r = 3 x (-2)² x (1)² x (3)

= 3 x (-2 x 1)² x (3) 

[Since a^m x b^m = (a x b)^m]

= 3 x (-2)² x (3)

= 3 x (-1)² x 2² x 3

= 3¹⁺¹ x 1 x 4 

[Since a^m x aⁿ = a^m+n]

= 3² x 4 = 9 x 4

∴ 3p²q²r = 36