Let the numerator & denominator be ‘n’ & ‘d’
Given that denominator exceeds numerator by 8
∴ d = n + 8
If numerator increased by 17 & denominator decreased by 1,
it becomes (n + 17) & (d – 1), fraction is 3/2.
i.e = (n+17)/(d−1) = 3/2 by cross multiplying, we get
(n+17)/(d−1) = 3/2
2(n + 17) = 3(d – 1)
2n + 2 x 17 = 3d – 3