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The denominator of a fraction exceeds its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get 3/2. Find the original fraction.

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Let the numerator & denominator be ‘n’ & ‘d’

Given that denominator exceeds numerator by 8

∴ d = n + 8

If numerator increased by 17 & denominator decreased by 1,

it becomes (n + 17) & (d – 1), fraction is 3/2.

i.e = (n+17)/(d−1) = 3/2 by cross multiplying, we get

(n+17)/(d−1) = 3/2

2(n + 17) = 3(d – 1)

2n + 2 x 17 = 3d – 3

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