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In triangle ABC, the measure of ∠B is two third the measure of ∠A. The measure of ∠C is 20° more than the measure of ∠A. Find the measures of the three angles.

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Let angle ∠A be a°

Given that ∠B = 2/3 x ∠A = 2/3a
& given ∠C = ∠A + 20 = a + 20

Since A, B & C are angles of a triangle, they add up to 180° (∆ property)

∠A + ∠B + ∠C = 180°

a + 2/3 a + a + 20 = 180°

(3a+2a+3a)/3 + 20 = 180°

8a/3 = 180 – 20 = 160°

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