Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Triangles by (23.5k points)
closed by

H is the orthocentre of ΔABC whose altitudes are AD, BE and CF. Then the orthocentre of ΔHBC is

(a) F 

(b) E 

(c) A 

(d) D

1 Answer

+1 vote
by (24.0k points)
selected by
 
Best answer

(c) A

H is the orthocentre of ΔABC 

⇒ AD ⊥ BC, BE ⊥ CA, CF ⊥ AB

In ΔBHC, 

AD ⊥ BC ⇒ HD ⊥ BC 

CF ⊥ AB ⇒ BF ⊥ HC (Produced) 

⇒ The altitudes HD and BF of ΔHBC intersect in A. 

⇒ A is the orthocentre of ΔHBC.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...