Question

Find sum of positive integral values of n for which (13n²+26n+6)/n is an integer

Answer 1

\(\frac{13n^2+26n+6}{n}\) = 13n + 26 + \(\frac{6}{n}\) is integer only when \(\frac{n}{6}\)

i.e, n = 1,2,3,6 only positive values of n for which \(\frac{13n^2+26n+6}{n}\) is integer.

Sum of these values of n = 1 + 2 + 3 + 6 = 12