Question

The diagonals of the rhombus is 12 cm and 16 cm. Find its perimeter. (Hint: the diagonals of rhombus bisect each other at right angles).

Answer 1

Here AO = CO = 8 cm

BO = DO = 6 cm

(∴ the diagonals of rhombus bisect each other at right angles)

∴ In ∆ AOB,

AB² = AO² + OB² = 8² + 6² = 64 + 36

= 100 = 10²

∴ AB = 10

Since it is a rhombus, all the four sides are equal.

AB = BC = CD = DA

∴ Its Perimeter = 10 + 10 + 10 + 10 = 40 cm