Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.8k views
in Chemistry by (45.9k points)
closed by

(i) What are the properties of resonance hybrid?

(ii) (CH3)3C+ (tert-Butyl carbocation) is more stable than (CH3)2C+H (sec-Propyl carbocation). Why?

1 Answer

+1 vote
by (44.0k points)
selected by
 
Best answer

(i) There are following properties of resonance hybrid:

(a) Stability: A resonance hybrid is more stable than any of the contributing structures. Greater the number of equivalent contributing structures of a molecule, greater will be the stability of the resonance hybrid.

(b) Resonance energy: It is equal to the difference between the energy of the resonance hybrid and of the most stable resonating structure. More the resonance energy of a molecule, greater is the stability due to resonance, e.g., the resonance energy of benzene is 151 kJ mol-1. It means benzene is more stable than any of its contributing structures by 151 kJ mol-1.

(c) Bond lengths: The bond lengths of resonance hybrid are always different from that of any of the contributing structures e.g., in benzene.

(ii) Tert-Butyl carbocation is more stable than sec-propyl carbocation due to hyperconjugation. Similarly, hydrogen of other two methyl groups can undergo hyperconjugation resulting in 10-resonance structures. However, in case of sec-propyl carbocation, only 7-resonance structures are possible.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...