We are given following for Air:

T_{1} = 300 K

T_{3} = T_{2} = 400K

P_{1} = 100kPa

V_{1} = V_{2} = 0.75 m^{3}

V_{3}^{ }=1.5m^{3}

From ideal gas EOS we can calculate air mass:

P_{1}.V = m.R.T_{1}

From table, corresponding to Air:

We can find term for stage 2 pressure using ideal gas EOS:

P_{1}.V = m.R.T_{1}

P_{2}.V = m.R.T_{2}

_{\(\frac{P_1}{T_1}\,=\frac{P_2}{T_2}\)}

P_{2} = \(\frac{P_1\,.\,T_2}{T_1}\) = \(\frac{100\,.\,400}{300}\)

P_{2} = 133.3kPa

We can find term for term for stage 3 pressure using ideal gas EOS for constant temperature Process:

P_{3}.V_{3} = m.R.T

P_{2}.V_{2} = m.R.T

P_{2}.V_{2} = P_{3}.V_{3} =

P_{3} = 66.7kPa

Work done in Process 1-2 is equal zero, because it is constant volume process:

W_{1-2 }= 0

Work done in process 2-3 :

Total work done in Process is equal to :

W = W_{1-2} + W_{2-3} = 69.3kJ

W = 69.3kJ

Total heat transfer is given by :

Q = m(u_{3}-u_{1}) + W

Q = m.C_{v}.ΔT + W

From Properties of ideal gas table we can find heat capacity of air :

C_{v} = 0.717\(\frac{kJ}{kgK}\)

Q = m.C_{v}.(T_{3}-T_{1}) + W = 0.871.0717.(400-300) + 69.3 = 131.75kJ