LIVE Course for free

Rated by 1 million+ students
Get app now
+3 votes
in Physics by (29.8k points)
edited by

Two objects of masses 100g and 200g are moving along the same line and direction with velocities of 2 ms -1 and 1 ms -1 , respectively. They collide and after the collision, the first object moves at a velocity of 1.67 ms -1 . Determine the velocity of the second object.

1 Answer

+3 votes
by (128k points)
selected by
Best answer

Mass of one of the objects, m1 = 100 g = 0.1 kg 

Mass of the other object, m2 = 200 g = 0.2 kg 

Velocity of m1 before collision, v1 = 2 m/s 

Velocity of m2 before collision, v2 = 1 m/s 

Velocity of m1 after collision, v3 = 1.67 m/s 

Velocity of m2 after collision = v4 

According to the law of conservation of momentum: 

Total momentum before collision = Total momentum after collision 

m1v1 + m2v2 = m1v3 + m2v

⇒ 0.1×2 + 0.2×1 = 0.1×1.67 + 0.2×v4 

⇒ 0.4 = 0.67 + 0.2×v4

⇒ v4 = 1.165 m/s 

Hence, the velocity of the second object becomes 1.165 m/s after the collision.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.