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If x = a cos θ and y = b sin θ, then b^2x^2 + a^2y^2 =

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If x = a cos θ and y = b sin θ, then b2x2 + a2y2 = 

A. a2b2 

B. ab 

C. a4b4 

D. a2 + b2

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Best answer

Given: x = a sin θ and y = b cos θ 

⇒ x2 = a2 sin2θ and y2 = b2 cos2θ ………(i) 

To find: b2x2 + a2y2 

Consider b2x2 + a2y2 = b2 a2 sin2θ + a2 b2 cos2θ 

= a2b2 (sin2θ + cos2θ) 

= a2b2 (1) [∵ sin2θ + cos2θ = 1] 

= a2b2

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