Question

Statement-1:A nucleus having energy `E_(1)` decays by `beta^(-)` emission to daugther nucleus having energy `E_(2)`, but the `beta^(-)` rays are emitted with a continuous energy spectrum having end point energy `(E_(1)-E_(2))`.
Statement-2: To conserve energy and momentum in `beta`-decay, at least three particles must take part in the transformation.
A. Statement-1 is correct but statement-2 is not correct
B. Statement-1 and statement-2 both are correct and statement-2 is the correct explanation of statement-1
C. Statement-1 is correct, statement is-2 is correct and statement -2 is not the correct explanation of statement-1
D. Statement-1 is incorrect, statement-2 is correct

Answer 1

Correct Answer - B
Statement-1: Energy of `beta`-particle from `0` to maximum so `E_(1)-E_(2)` is the continuous energy spectrum.
Statement-2: For energy conservation and momentum at least three particles daughter nucleus `+beta^(-1)` and antineutron.