Question

The `K_(alpha) X`-ray emission line of tungsten occurs at `lambda = 0.021 nm`. The energy difference between K and L levels in this aotm is about : `0.51 MeV`
A. `0.51 MeV`
B. `1.2 MeV`
C. `59 keV`
D. `13.6 eV`

Answer 1

Correct Answer - C
`E = (hc)/(lambda) = (1242eV - nm)/(0.021 nm) = 59 keV`