Question

If discharge rate is given by `V=(pi Pr^(4))/(8 mu l)` then find out the dimensions of `mu` by taking velocity (v), time (T) and mass (M) as fundamental units.

Answer 1

`because mu=(piPr^(4))/(8V l) therefore "Dimension of" mu:((MLT^(-2)L^(-2))(L^(4)))/((L^(3)T^(-1))(L))=ML^(-1)T^(-1)`
Also `v=LT^(-1)rArr L=vT therefore "Dimension of" mu "are" M(vT)^(-1)T^(-1)=Mv^(-1)T^(-2)`