Taking log both sides
log ( f(x) ) = log ( e2x ) + log ( sin(3x)) - ½ log ( 1 + x2 )
log ( f(x) ) = 2x + log ( sin(3x)) - ½ log ( 1 + x2 )
Differentiating w.r.to x
1/f(x) . f’(x) = 2 + 3 cot(3x) - ½ (2x)/(1+ x2)
. f’(x) = [ 2 + 3 cot(3x) - x/(1+ x2) ] (e2x sin (3x))/sqrt( 1 + x2 )