Question

Let a, b be two distinct values of x lying in [0,π] for which √5 sin x, 10 sin x, 10(4 sin² x + 1) are 3 consecutive terms of a G.P. Then minimum value of |a – b| =

Answer 1

\(10 \sin x = \sqrt 5 (4\sin^2 x + 1)\)

\(\Rightarrow \sin x = \frac{\sqrt 5 + 1}4\)